Question:

In the figure given below, ABCD is a rectangle. The area of the isosceles right triangle ABE = 7 \(cm^2\); EC = 3(BE). The area of ABCD (in \(cm^2\)) is

Show Hint

In the figure E lies on side BC and the right angle of the isosceles triangle ABE is at B, so AB = BE. Express BC in terms of BE.
Updated On: Nov 4, 2026
  • 21 \(cm^2\)
  • 56 \(cm^2\)
  • 42 \(cm^2\)
  • 28 \(cm^2\)
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Step 1: Triangle ABE.
The right angle is at B and the triangle is isosceles, so \(AB = BE = a\). Its area is \(\tfrac12 a^2 = 7\), so \(a^2 = 14\).

Step 2: Side BC.
E lies on BC and \(EC = 3\,BE = 3a\). Hence \(BC = BE + EC = 4a\).

Step 3: Rectangle.
\[ [ABCD] = AB \times BC = a \times 4a = 4a^2 = 4 \times 14 = 56\ cm^2. \]

Final Answer:
The correct option is (2): 56 \(cm^2\)
Was this answer helpful?
0
0

Top CAT Quantitative Aptitude Questions

View More Questions

Top CAT Geometry Questions

View More Questions