In the figure given below, ABCD is a rectangle. The area of the isosceles right triangle ABE = 7 \(cm^2\); EC = 3(BE). The area of ABCD (in \(cm^2\)) is
Show Hint
In the figure E lies on side BC and the right angle of the isosceles triangle ABE is at B, so AB = BE. Express BC in terms of BE.