Question

In the equilibrium mixture, \(KI + I_2 \rightleftharpoons KI_3\), the concentration of \(KI\) and \(I_2\) is made two fold and three fold respectively. The concentration of \(KI_3\) becomes

• A. two fold
• B. three fold
• C. five fold
• D. six fold

Hint:

For equilibrium problems, focus on how concentration changes affect the equilibrium expression while keeping \(K_c\) constant at fixed temperature.

Answer 1

The Correct Option is A

Concept: \[ K_c = \frac{[KI_3]}{[KI][I_2]} \]

Step 1: Apply changes.
\[ [KI]' = 2[KI], \quad [I_2]' = 3[I_2] \]

Step 2: New equilibrium.
System shifts to maintain equilibrium constant \(K_c\).

Step 3: Conclusion.
Concentration of \(KI_3\) becomes two fold.