Concept: Gauss’s Law
\[
\Phi = \frac{Q_{\text{enclosed}}}{\varepsilon_0}
\]
Electric flux through a closed surface depends only on the charge enclosed inside the surface.
Step 1: Identify charges
From diagram:
• Charge $+q$ is inside surface $S$
• Charge $-2q$ is outside surface $S$
Step 2: Apply Gauss’s law
Only enclosed charge contributes:
\[
Q_{\text{enclosed}} = +q
\]
\[
\Phi = \frac{q}{\varepsilon_0}
\]
Conclusion:
External charges do not affect net flux.
Final Answer: Option (A)