Question

In the combination of the following gates the output Y can be written in terms of inputs A and B as

• A. \(\overline{A.B}\)
• B. \(\overline{A.B}+A.B\)
• C. \(A.\overline{B}+\overline{A}.B\)
• D. \(\overline{A+B}\)

Answer 1

The Correct Option is C

To determine the output \( Y \) in terms of inputs \( A \) and \( B \), analyze the circuit step-by-step.

1. Inputs are \( A \) and \( B \).
2. NOT gates produce: \( \overline{A} \) and \( \overline{B} \).
3. First AND gate: \( \overline{A} \cdot B \)
4. Second AND gate: \( A \cdot \overline{B} \)
5. Outputs of both AND gates go to an OR gate.
6. Final output: \[ Y = A \cdot \overline{B} + \overline{A} \cdot B \]

This is the standard expression of an XOR gate.

Final Answer: \( Y = A \cdot \overline{B} + \overline{A} \cdot B \)