Question:

In the circuit shown in the figure, find the current in the 45Ω resistor. 

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In symmetric resistor networks: • Nodes at the same level have equal potential • Resistors between equipotential points carry no current This greatly simplifies circuit analysis.
Updated On: Mar 19, 2026
  • \(4\,\text{A}\)
  • \(2.5\,\text{A}\)
  • \(2\,\text{A}\)
  • None of these
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The Correct Option is B

Solution and Explanation


Step 1:
Observe that the circuit is symmetric about the vertical axis passing through the top node and the bottom junction.
Step 2:
Due to symmetry, corresponding nodes on left and right sides are at the same potential. Hence, no current flows through the central 90Ω resistor.
Step 3:
Reduce the circuit using series–parallel combinations. The equivalent resistance of each side branch simplifies, and the total equivalent resistance of the circuit is: Rₑq = 72Ω
Step 4:
Total current from the 180V source: Itotal = (180)/(72) = 2.5A
Step 5:
This current flows through the 45Ω resistor, hence: I₄5Ω = 2.5A
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