In the circuit given below, V(t) is the sinusoidal voltage source. Voltage drop VAB(t) across the resistance R is 
Step 1: During the positive half cycle of V(t):
• Diode D₁ is forward biased • Diode D₂ is reverse biased • Current flows through R₁ and R
Step 2: During the negative half cycle of V(t):
• Diode D₁ is reverse biased • Diode D₂ is forward biased • Current flows through R₂ and R
Step 3: Since R₁ ≠ R₂, the current magnitude (and hence voltage drop across R) is different in the two half cycles. ⟹ VAB(t) has different peak values in positive and negative half cycles.
The equivalent resistance between the points \(A\) and \(B\) in the given circuit is \[ \frac{x}{5}\,\Omega. \] Find the value of \(x\). 
An infinitely long straight wire carrying current $I$ is bent in a planar shape as shown in the diagram. The radius of the circular part is $r$. The magnetic field at the centre $O$ of the circular loop is :
