Question:
In the case of a wire, having negligible mass suspended from ceiling and stretched under the action of a weight \(F\) suspended from its other end, the tension at any cross-section of the wire is
In the case of a wire, having negligible mass suspended from ceiling and stretched under the action of a weight \(F\) suspended from its other end, the tension at any cross-section of the wire is
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In a massless string or wire under equilibrium, tension is uniform throughout the string. If a force \(F\) stretches it, the tension at every cross-section is \(F\).
Updated On: Jun 18, 2026
- Zero
- \(2F\)
- \(0.5F\)
- \(F\)
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The Correct Option is D
Solution and Explanation
Step 1: Understand the given situation.
A wire of negligible mass is suspended from the ceiling.
A weight \(F\) is attached to its lower end.
Since the wire is assumed to have negligible mass, its own weight is ignored.
Step 2: Analyze the force balance.
The weight \(F\) pulls the wire downward.
For the system to remain in equilibrium, the wire must exert an equal upward force.
Hence, the tension developed in the wire must balance the applied weight.
Step 3: Tension in a massless wire.
For a massless wire or string, the tension remains the same throughout its length.
Therefore, at every cross-section of the wire, the tension is \[ T=F. \]
Step 4: Final conclusion.
Thus, the tension at any cross-section of the wire is \[ \boxed{F} \]
A wire of negligible mass is suspended from the ceiling.
A weight \(F\) is attached to its lower end.
Since the wire is assumed to have negligible mass, its own weight is ignored.
Step 2: Analyze the force balance.
The weight \(F\) pulls the wire downward.
For the system to remain in equilibrium, the wire must exert an equal upward force.
Hence, the tension developed in the wire must balance the applied weight.
Step 3: Tension in a massless wire.
For a massless wire or string, the tension remains the same throughout its length.
Therefore, at every cross-section of the wire, the tension is \[ T=F. \]
Step 4: Final conclusion.
Thus, the tension at any cross-section of the wire is \[ \boxed{F} \]
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