Question:
In simple harmonic motion, at mean position
In simple harmonic motion, at mean position
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Mean position means zero displacement, so zero potential energy and maximum kinetic energy!
Updated On: Jun 3, 2026
- KE maximum
- PE maximum
- KE zero
- Acceleration maximum
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The Correct Option is A
Solution and Explanation
Step 1: Concept
In Simple Harmonic Motion (SHM), the total mechanical energy of the system is conserved and is continuously transformed between kinetic energy (KE) and potential energy (PE).
Step 2: Meaning
The mean position refers to the equilibrium position where the displacement of the particle from its central point is zero ($x = 0$).
Step 3: Analysis
Since potential energy is given by $\frac{1}{2}kx^2$, at $x=0$, the potential energy is minimum (zero). Consequently, by conservation of energy, the velocity of the particle reaches its maximum value ($v = \omega A$), making the kinetic energy maximum. The acceleration, being proportional to displacement ($a = -\omega^2 x$), is also zero at this point.
Step 4: Conclusion
Therefore, at the mean position, the kinetic energy of the particle is maximum.
Final Answer: (A)
In Simple Harmonic Motion (SHM), the total mechanical energy of the system is conserved and is continuously transformed between kinetic energy (KE) and potential energy (PE).
Step 2: Meaning
The mean position refers to the equilibrium position where the displacement of the particle from its central point is zero ($x = 0$).
Step 3: Analysis
Since potential energy is given by $\frac{1}{2}kx^2$, at $x=0$, the potential energy is minimum (zero). Consequently, by conservation of energy, the velocity of the particle reaches its maximum value ($v = \omega A$), making the kinetic energy maximum. The acceleration, being proportional to displacement ($a = -\omega^2 x$), is also zero at this point.
Step 4: Conclusion
Therefore, at the mean position, the kinetic energy of the particle is maximum.
Final Answer: (A)
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