Question:

In parallel resonance circuit, the current:

Show Hint

In reactive branches, capacitive current leads by \(90^\circ\) and inductive current lags by \(90^\circ\).
Updated On: May 19, 2026
  • leads the emf by a phase angle of \(\dfrac{\pi}{2}\)
  • lags the emf by a phase angle of \(\dfrac{\pi}{4}\)
  • leads or lags the emf by a phase angle of \(\pi\)
  • leads or lags the emf by a phase angle of \(\dfrac{\pi}{2}\)
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

Concept:
In a parallel resonant circuit, the inductor and capacitor branch currents are reactive in nature.

Step 1: Current in capacitor branch.

In a capacitor, current leads the applied emf by: \[ \frac{\pi}{2} \]

Step 2: Current in inductor branch.

In an inductor, current lags the applied emf by: \[ \frac{\pi}{2} \]

Step 3: Apply resonance condition.

At parallel resonance, inductive and capacitive reactive currents are equal and opposite in phase. Thus, the branch currents may lead or lag the emf by: \[ \frac{\pi}{2} \] \[ \therefore \text{Correct Answer is (D)} \]
Was this answer helpful?
0
0

Top CUET PG Geophysics Questions

View More Questions