Concept:
In a parallel resonant circuit, the inductor and capacitor branch currents are reactive in nature.
Step 1: Current in capacitor branch.
In a capacitor, current leads the applied emf by:
\[
\frac{\pi}{2}
\]
Step 2: Current in inductor branch.
In an inductor, current lags the applied emf by:
\[
\frac{\pi}{2}
\]
Step 3: Apply resonance condition.
At parallel resonance, inductive and capacitive reactive currents are equal and opposite in phase.
Thus, the branch currents may lead or lag the emf by:
\[
\frac{\pi}{2}
\]
\[
\therefore \text{Correct Answer is (D)}
\]