Question

In hydrogen atom, transition from the state \( n = 6 \) to \( n = 1 \) results in ultraviolet radiation. Infrared radiation will be obtained in the transition

• A. \( n = 3 \text{ to } n = 1 \)
• B. \( n = 4 \text{ to } n = 2 \)
• C. \( n = 6 \text{ to } n = 2 \)
• D. \( n = 5 \text{ to } n = 3 \)

Hint:

Lyman $\to$ UV, Balmer $\to$ Visible, Others $\to$ Infrared.

Answer 1

The Correct Option is D

Step 1: Concept
In Hydrogen spectrum, transitions to $n=1$ (Lyman) are UV, to $n=2$ (Balmer) are Visible, and to $n=3, 4, 5$ (Paschen, Brackett, Pfund) are Infrared.
Step 2: Analysis of Options
(A) To $n=1$: UV.
(B) & (C) To $n=2$: Visible.
(D) To $n=3$ (Paschen series): Infrared.
Step 3: Conclusion
The transition $n=5 \to n=3$ falls in the Infrared region.
Final Answer:(D)