Question:

In hydrogen atom, an electron of charge 'e' revolves in an orbit of radius 'r' with speed 'v'. The magnetic moment associated with electron is

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The ratio of magnetic moment to angular momentum ($L = mvr$) is constant: $\frac{M}{L} = \frac{e}{2m}$.
Updated On: Apr 30, 2026
  • \( \frac{evr}{3} \)
  • \( \frac{evr}{2} \)
  • evr
  • \( \sqrt{2}evr \)
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The Correct Option is B

Solution and Explanation

Step 1: Concept
Magnetic moment ($M$) of a revolving electron is $M = I \times A$.
Step 2: Current and Area
Current $I = \frac{e}{T} = \frac{e}{(2\pi r / v)} = \frac{ev}{2\pi r}$
Area $A = \pi r^2$
Step 3: Calculation
$M = \left( \frac{ev}{2\pi r} \right) \times (\pi r^2)$
$M = \frac{evr}{2}$
Step 4: Conclusion
The magnetic moment is $\frac{evr}{2}$.
Final Answer:(B)
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