Question:
In Gatterman reaction, which of the following catalyst is used?
In Gatterman reaction, which of the following catalyst is used?
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Gattermann reaction uses copper powder with HX, while Sandmeyer uses Cu(I) salts.
Updated On: Oct 1, 2026
- CO, HCl and anhyd. \(\text{AlCl}_3\)
- Copper powder and HBr
- Cu + Aq. \(\text{NaNO}_2\)
- KOH + \(\text{Br}_2\)
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept:
The Gattermann reaction converts a benzenediazonium salt to an aryl halide using copper powder and the halogen acid (HCl or HBr).
Step 2: Write the reaction:
\[ \text{ArN}_2^+\text{X}^- \xrightarrow{\text{Cu powder, HBr}} \text{ArBr} + \text{N}_2 \]
Step 3: Match with the options:
Option B, copper powder and HBr, is the Gattermann catalyst system. Option A (CO, HCl, anhydrous \(\text{AlCl}_3\)) is the Gattermann-Koch reaction. Option C is not a reagent set for aryl halides. Option D (KOH + \(\text{Br}_2\)) is the Hofmann bromamide reagent.
Step 4: Conclusion:
Copper powder and HBr, option B.
Final Answer:
The Gattermann reaction uses copper powder and HBr. \[ \boxed{\text{(B) }\text{Copper powder and HBr}} \]
The Gattermann reaction converts a benzenediazonium salt to an aryl halide using copper powder and the halogen acid (HCl or HBr).
Step 2: Write the reaction:
\[ \text{ArN}_2^+\text{X}^- \xrightarrow{\text{Cu powder, HBr}} \text{ArBr} + \text{N}_2 \]
Step 3: Match with the options:
Option B, copper powder and HBr, is the Gattermann catalyst system. Option A (CO, HCl, anhydrous \(\text{AlCl}_3\)) is the Gattermann-Koch reaction. Option C is not a reagent set for aryl halides. Option D (KOH + \(\text{Br}_2\)) is the Hofmann bromamide reagent.
Step 4: Conclusion:
Copper powder and HBr, option B.
Final Answer:
The Gattermann reaction uses copper powder and HBr. \[ \boxed{\text{(B) }\text{Copper powder and HBr}} \]
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