The distance between consecutive antinodes is equal to the wavelength.
In a pipe open at both ends when an air column is vibrated, only even harmonics are present.
When an air column is vibrated in a pipe closed at one end, all harmonics are present.
In the case of a stretched string, when vibrated frequency of the first overtone is same as the second harmonic.
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The Correct Option isD
Solution and Explanation
Step 1: Understanding the Concept
A harmonic is a multiple of the fundamental frequency. The first overtone is the first frequency above the fundamental.
Step 2: Detailed Explanation
(A) Consecutive antinodes are separated by \(\lambda/2\), not by a full wavelength.
(B) A pipe open at both ends supports all harmonics, both even and odd.
(C) A pipe closed at one end supports only odd harmonics.
(D) For a stretched string, the fundamental is the first harmonic, and the next frequency, the first overtone, is \(2f_0\), the second harmonic. This statement is correct.
Final Answer:
Statement (D) is correct, option (D).
\[ \boxed{\text{(D)}} \]