Question:
In Boolean algebra, \(A+AB\) is equal to
In Boolean algebra, \(A+AB\) is equal to
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Absorption law: \(A+AB=A\).
Updated On: May 27, 2026
- \(A\)
- \(B\)
- \(AB\)
- \(A+B\)
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The Correct Option is A
Solution and Explanation
Concept:
This problem is based on the absorption law of Boolean algebra.
Step 1: Given expression: \[ A+AB \]
Step 2: Take \(A\) common. \[ A+AB=A(1+B) \]
Step 3: In Boolean algebra: \[ 1+B=1 \]
Step 4: Therefore: \[ A(1+B)=A\cdot1=A \] Hence: \[ \boxed{A} \]
Step 1: Given expression: \[ A+AB \]
Step 2: Take \(A\) common. \[ A+AB=A(1+B) \]
Step 3: In Boolean algebra: \[ 1+B=1 \]
Step 4: Therefore: \[ A(1+B)=A\cdot1=A \] Hence: \[ \boxed{A} \]
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