In Bohr’s model, the radius of an orbit is given by:
$r_n = \dfrac{n^2 h^2}{4\pi^2 m e^2 Z} \propto \dfrac{n^2}{Z}$
Where:
- $n$ is the principal quantum number
- $Z$ is the atomic number
- For ground state, $n = 1$
Let’s compare the radii:
Hydrogen (H): $Z = 1$, so $r_1 \propto \dfrac{1^2}{1} = 1$
Helium ion (He⁺): $Z = 2$, so $r_2 \propto \dfrac{1^2}{2} = \dfrac{1}{2}$
So,
$\dfrac{r_2}{r_1} = \dfrac{1/2}{1} = \mathbf{\dfrac{1}{2}}$
Answer: $\dfrac{r_2}{r_1} = \dfrac{1}{2}$
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