Question:

In any $\Delta ABC$, $a(b \cos C-c \cos B)$ equals

Show Hint

Standard cosine rule: $\cos C = \frac{a^2+b^2-c^2}{2ab}$.
Updated On: Apr 10, 2026
  • $b^{2}+c^{2}$
  • $b^{2}-c^{2}$
  • $\frac{1}{b}+\frac{1}{c}$
  • $\frac{1}{b^{2}}-\frac{1}{c^{2}}$
Show Solution
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The Correct Option is B

Solution and Explanation

Step 1: Expand
$ab \cos C - ac \cos B$.
Step 2: Cosine Rule

$ab(\frac{a^2+b^2-c^2}{2ab}) - ac(\frac{a^2+c^2-b^2}{2ac})$.
Step 3: Simplify

$\frac{a^2+b^2-c^2}{2} - \frac{a^2+c^2-b^2}{2} = \frac{2b^2 - 2c^2}{2} = b^2 - c^2$.
Final Answer: (B)
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