Question:

In an \(LC\) circuit, angular frequency at resonance is \(\omega\). The new angular frequency when inductance is made four times and capacitance is made eight times is

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Resonant frequency is inversely proportional to the square root of the product of L and C.
Updated On: Apr 30, 2026
  • \(\frac{\omega}{2\sqrt{2}}\)
  • \(\frac{\omega}{4\sqrt{2}}\)
  • \(\frac{\omega}{4}\)
  • \(\frac{\omega}{\sqrt{2}}\)
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The Correct Option is B

Solution and Explanation


Step 1: Formula

The resonant angular frequency is given by $\omega = \frac{1}{\sqrt{LC}}$.

Step 2: Analysis

New inductance $L' = 4L$ and new capacitance $C' = 8C$.
$\omega' = \frac{1}{\sqrt{L'C'}} = \frac{1}{\sqrt{4L \times 8C}}$.

Step 3: Calculation

$\omega' = \frac{1}{\sqrt{32LC}} = \frac{1}{4\sqrt{2} \cdot \sqrt{LC}}$.
$\omega' = \frac{\omega}{4\sqrt{2}}$.
Final Answer: (B)
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