Question:

In an isothermal expansion of an ideal gas, the heat supplied to the gas is:

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For an ideal gas: \[ \Delta U = 0 \] whenever temperature remains constant. Hence, in isothermal expansion, all supplied heat is used to perform work.
Updated On: May 19, 2026
  • entirely used to increase internal energy
  • entirely used to do work
  • partly used to do work and partly to increase internal energy
  • none of the above
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The Correct Option is B

Solution and Explanation

Concept: According to the First Law of Thermodynamics: \[ \Delta U = q - w \] For an ideal gas, internal energy depends only on temperature.

Step 1:
Understanding the meaning of isothermal process.
In an isothermal process: \[ T = \text{constant} \] Therefore, \[ \Delta T = 0 \]

Step 2:
Relating temperature to internal energy.
For an ideal gas: \[ \Delta U \propto \Delta T \] Since \(\Delta T = 0\): \[ \Delta U = 0 \]

Step 3:
Applying First Law of Thermodynamics.
\[ \Delta U = q - w \] Substituting \(\Delta U = 0\): \[ 0 = q - w \] \[ q = w \] This means the entire heat supplied is converted into work done by the gas.
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