The correct answer is (A) : 27.5 cm
Given: u= -20cm
f= 15 cm
distance (d) of convex lens= 5cm

By substituting the values in equation (1) we get,
\(\frac{1}{v}+\frac{1}{20}=\frac{1}{15}\)
\(⇒\frac{1}{v}=\frac{1}{15}-\frac{1}{20}\)
\(⇒\frac{1}{v}=\frac{5}{300}\)
\(⇒v=\frac{300}{5}\)
\(⇒v=60\ cm\)
Thus, the image will be formed at 60cm to the right of the lens and it will be inverted.
Therefore, distance between lens and mirror will be
d = image distance – radius of curvature of convex mirror
\(d = v -2f\)
By substituting the values in above equation we get,
\(5 = 60 - R\)
\(⇒ R = 55\)
But, the radius of curvature (R) is given by,
\(R=2f\)
\(⇒f=\frac{55}{2}\)
\(⇒f=27.5\)
Hence , the focal length of the convex mirror is 27.5cm.
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