Question

In an electric circuit shown, each cell has e.m.f. \(2V\) and internal resistance \(1\Omega\). The external resistance is \(2\Omega\). The value of current (in A) is

• A. \(2\)
• B. \(1.25\)
• C. \(0.4\)
• D. \(1.2\)

Hint:

The cells are connected in series with the same polarity, so emfs and internal resistances add.

Answer 1

The Correct Option is D

Step 1: Understanding the Concept
Three identical cells in series with matching polarity give total emf \(3E\) and total internal resistance \(3r\).

Step 2: Totals
\(E_{total}=3\times2=6\) V and \(r_{total}=3\times1=3\ \Omega\).

Step 3: Current
\(I=\dfrac{E_{total}}{R+r_{total}}=\dfrac{6}{2+3}\).

Step 4: Result
\(I=1.2\) A, option (D).

Final Answer:
The current in the circuit is 1.2 A. \[ \boxed{\text{(D) }1.2} \]