Understanding the RMS (Root Mean Square) Value:
The root mean square (rms) value \( I_{\text{rms}} \) of a current \( i = I_0 + I_1 \sin(\omega t + \phi) \) is given by:
\[ I_{\text{rms}} = \sqrt{(I_0)^2 + \frac{(I_1)^2}{2}} \] where \( I_0 \) is the DC component and \( I_1 \) is the amplitude of the AC component.
Identify \( I_0 \) and \( I_1 \):
In this case:
\[ I_0 = 6 \, \text{A} \quad \text{and} \quad I_1 = \sqrt{56} \, \text{A} \]
Calculate the RMS Value:
Substitute \( I_0 = 6 \) and \( I_1 = \sqrt{56} \) into the rms formula:
\[ I_{\text{rms}} = \sqrt{(6)^2 + \frac{(\sqrt{56})^2}{2}} \] \[ = \sqrt{36 + \frac{56}{2}} \] \[ = \sqrt{36 + 28} \] \[ = \sqrt{64} = 8 \, \text{A} \]
Conclusion:
The rms value of the current is \( 8 \, \text{A} \).
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)