Understanding the RMS (Root Mean Square) Value:
The root mean square (rms) value \( I_{\text{rms}} \) of a current \( i = I_0 + I_1 \sin(\omega t + \phi) \) is given by:
\[ I_{\text{rms}} = \sqrt{(I_0)^2 + \frac{(I_1)^2}{2}} \] where \( I_0 \) is the DC component and \( I_1 \) is the amplitude of the AC component.
Identify \( I_0 \) and \( I_1 \):
In this case:
\[ I_0 = 6 \, \text{A} \quad \text{and} \quad I_1 = \sqrt{56} \, \text{A} \]
Calculate the RMS Value:
Substitute \( I_0 = 6 \) and \( I_1 = \sqrt{56} \) into the rms formula:
\[ I_{\text{rms}} = \sqrt{(6)^2 + \frac{(\sqrt{56})^2}{2}} \] \[ = \sqrt{36 + \frac{56}{2}} \] \[ = \sqrt{36 + 28} \] \[ = \sqrt{64} = 8 \, \text{A} \]
Conclusion:
The rms value of the current is \( 8 \, \text{A} \).
The figure shows a pipe with cross-section area 10 \( cm^2 \). Water flows from one end with velocity 20 cm/s. The other end of the pipe is closed and consists of 10 holes each of area 30 \( mm^2 \). Find the velocity of water coming out from each hole: 
Which of the following best represents the temperature versus heat supplied graph for water, in the range of \(-20^\circ\text{C}\) to \(120^\circ\text{C}\)? 


Find capacitance $C$ for the given circuit.
Given: \( L = 20\text{ H}, \quad R = 100\Omega, \quad \omega = 100\text{ rad/s} \)
The applied voltage and current are: \[ V = V_0 \sin \omega t, \quad i = i_0 \sin \omega t \]

The figure shows a pipe with cross-section area 10 \( cm^2 \). Water flows from one end with velocity 20 cm/s. The other end of the pipe is closed and consists of 10 holes each of area 30 \( mm^2 \). Find the velocity of water coming out from each hole: 
Which of the following best represents the temperature versus heat supplied graph for water, in the range of \(-20^\circ\text{C}\) to \(120^\circ\text{C}\)? 