Question:
In aldol condensation reaction, 1,3-diphenylprop-2-en-1-one is obtained as major product in the reaction between
In aldol condensation reaction, 1,3-diphenylprop-2-en-1-one is obtained as major product in the reaction between
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Benzaldehyde + acetophenone in base gives chalcone, a common named aldol condensation product.
Updated On: Apr 24, 2026
- benzaldehyde and benzophenone
- benzaldehyde and acetophenone
- propan-2-one and benzaldehyde
- acetophenone and propan-2-one
- benzaldehyde and butan-2-one
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The Correct Option is B
Solution and Explanation
Concept:
Cross aldol condensation between an aromatic aldehyde and ketone forms $\alpha,\beta$-unsaturated ketone.
Step 1: Identify product structure.
Given product: \[ \text{1,3-diphenylprop-2-en-1-one} \] This is chalcone.
Step 2: Recognize formation of chalcone.
Chalcone is prepared by Claisen-Schmidt condensation of: \[ \text{benzaldehyde} + \text{acetophenone} \]
Step 3: Reason.
- Benzaldehyde has no $\alpha$-hydrogen. - Acetophenone forms enolate ion. - Condensation followed by dehydration gives chalcone.
Step 4: Final answer.
\[ \boxed{\text{benzaldehyde and acetophenone}} \]
Hence, correct option is (B).
Cross aldol condensation between an aromatic aldehyde and ketone forms $\alpha,\beta$-unsaturated ketone.
Step 1: Identify product structure.
Given product: \[ \text{1,3-diphenylprop-2-en-1-one} \] This is chalcone.
Step 2: Recognize formation of chalcone.
Chalcone is prepared by Claisen-Schmidt condensation of: \[ \text{benzaldehyde} + \text{acetophenone} \]
Step 3: Reason.
- Benzaldehyde has no $\alpha$-hydrogen. - Acetophenone forms enolate ion. - Condensation followed by dehydration gives chalcone.
Step 4: Final answer.
\[ \boxed{\text{benzaldehyde and acetophenone}} \]
Hence, correct option is (B).
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