Question:
In acidic solution, permanganate ion is reduced by ferrous ion.
The number of electrons involved in the reduction of permanganate ion is ............
In acidic solution, permanganate ion is reduced by ferrous ion.
The number of electrons involved in the reduction of permanganate ion is ............
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Always determine oxidation state change to find electrons in redox reactions.
Updated On: Dec 14, 2025
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Correct Answer: 5
Solution and Explanation
Step 1: Write oxidation state change.
Mn in \(\text{MnO}_4^{-}\): +7 Mn in \(\text{Mn}^{2+}\): +2 Step 2: Calculate change in oxidation state.
\[ 7 \rightarrow 2\quad \Rightarrow\quad \Delta = 5\ \text{electrons} \] Step 3: Balanced half-reaction (acidic medium).
\[ \text{MnO}_4^{-} + 8H^{+} + 5e^{-} \rightarrow \text{Mn}^{2+} + 4H_2O \] Step 4: Conclusion.
Number of electrons gained = 5.
Mn in \(\text{MnO}_4^{-}\): +7 Mn in \(\text{Mn}^{2+}\): +2 Step 2: Calculate change in oxidation state.
\[ 7 \rightarrow 2\quad \Rightarrow\quad \Delta = 5\ \text{electrons} \] Step 3: Balanced half-reaction (acidic medium).
\[ \text{MnO}_4^{-} + 8H^{+} + 5e^{-} \rightarrow \text{Mn}^{2+} + 4H_2O \] Step 4: Conclusion.
Number of electrons gained = 5.
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