Question:
Fehling’s solution
Fehling’s solution
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Fehling’s test: aldehyde or reducing sugar → brick-red Cu$_2$O precipitate.
Updated On: Dec 14, 2025
- contains a copper complex of tartaric acid
- forms a brick-red precipitate with glucose
- forms a white precipitate with aldehydes
- is used as a test reagent for reducing sugars
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The Correct Option is A, B, D
Solution and Explanation
Step 1: Recall composition of Fehling’s solution.
Fehling’s reagent contains Cu$^{2+}$ ions complexed with tartrate in an alkaline medium. It is used to detect reducing sugars.
Step 2: Identify reactions.
Aldehydes reduce Cu$^{2+}$ → Cu$_2$O, giving a brick-red precipitate. Thus, option (B) is true, and (D) is also true. (A) is also correct regarding chemical composition.
Step 3: Determine incorrect statement.
(C) is incorrect because aldehydes do NOT form a white precipitate; they form a brick-red precipitate of Cu$_2$O.
Step 4: Conclusion.
Thus, the incorrect statement (and the expected answer) is (C).
Fehling’s reagent contains Cu$^{2+}$ ions complexed with tartrate in an alkaline medium. It is used to detect reducing sugars.
Step 2: Identify reactions.
Aldehydes reduce Cu$^{2+}$ → Cu$_2$O, giving a brick-red precipitate. Thus, option (B) is true, and (D) is also true. (A) is also correct regarding chemical composition.
Step 3: Determine incorrect statement.
(C) is incorrect because aldehydes do NOT form a white precipitate; they form a brick-red precipitate of Cu$_2$O.
Step 4: Conclusion.
Thus, the incorrect statement (and the expected answer) is (C).
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