Question:

In a Young's double slit experiment two slits are separated by 2 mm and the screen is placed one meter away. When a light of wavelength 500 nm is used, the fringe separation will be :

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Fringe width \(\beta=\frac{\lambda D}{d}\).
Updated On: Nov 4, 2026
  • 0.50 mm
  • 0.25 mm
  • 1 mm
  • 0.75 mm
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The Correct Option is B

Solution and Explanation

\(\beta=\frac{\lambda D}{d}=\frac{500\times10^{-9}\times1}{2\times10^{-3}}=2.5\times10^{-4}\) m \(=0.25\) mm.
Answer: (2) 0.25 mm
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