Concept:
Let the angles of the triangle be \( 4k, 1k, 1k \). Since the sum of angles in a triangle is \( 180^{\circ} \):
\[
4k + 1k + 1k = 180^{\circ} \implies 6k = 180^{\circ} \implies k = 30^{\circ}
\]
Thus, the three angles are \( A = 120^{\circ} \), \( B = 30^{\circ} \), and \( C = 30^{\circ} \).
According to the Law of Sines, side lengths are directly proportional to the sines of their opposite angles: \( a : b : c = sin~A : sin~B : sin~C \).
Step 1: Evaluating side length proportions.
\[
a : b : c = sin(120^{\circ}) : sin(30^{\circ}) : sin(30^{\circ})
\]
\[
= \frac{\sqrt{3}}{2} : \frac{1}{2} : \frac{1}{2} = \sqrt{3} : 1 : 1
\]
We can set the sides as \( a = \sqrt{3}x \), \( b = 1x \), and \( c = 1x \).
Step 2: Determining largest side and perimeter values.
The largest side is opposite the largest angle (\( 120^{\circ} \)), which is:
\[
\text{Largest side} = a = \sqrt{3}x
\]
The total perimeter of the triangle is the sum of all three sides:
\[
\text{Perimeter} = a + b + c = \sqrt{3}x + 1x + 1x = (2 + \sqrt{3})x
\]
Step 3: Calculating the required ratio.
\[
\text{Ratio} = \frac{\text{Largest side}}{\text{Perimeter}} = \frac{\sqrt{3}x}{(2+\sqrt{3})x} = \frac{\sqrt{3}}{2+\sqrt{3}}
\]