Question:
In a stationary wave, what is the distance between a node and an adjacent antinode?
In a stationary wave, what is the distance between a node and an adjacent antinode?
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Standing wave distances:
Node to Node = $\lambda/2$
Antinode to Antinode = $\lambda/2$
Node to Antinode = $\lambda/4$.
Updated On: Apr 23, 2026
- $\lambda/2$
- $\lambda/4$
- $\lambda/8$
- $\lambda$
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The Correct Option is B
Solution and Explanation
Concept:
A stationary wave (or standing wave) is formed by the superposition of two waves of the same frequency and amplitude traveling in opposite directions. This results in fixed points called nodes and antinodes.
Step 1: Understanding nodes and antinodes
• Node: A point where the displacement is always zero.
• Antinode: A point where the displacement is maximum.
Step 2: Distance relationships in stationary waves
In a stationary wave:
• Distance between two consecutive nodes = $\lambda/2$
• Distance between two consecutive antinodes = $\lambda/2$
• Distance between a node and the nearest antinode = $\lambda/4$ Conclusion:
Therefore, the distance between a node and the adjacent antinode is $\mathbf{\lambda/4}$.
A stationary wave (or standing wave) is formed by the superposition of two waves of the same frequency and amplitude traveling in opposite directions. This results in fixed points called nodes and antinodes.
Step 1: Understanding nodes and antinodes
• Node: A point where the displacement is always zero.
• Antinode: A point where the displacement is maximum.
Step 2: Distance relationships in stationary waves
In a stationary wave:
• Distance between two consecutive nodes = $\lambda/2$
• Distance between two consecutive antinodes = $\lambda/2$
• Distance between a node and the nearest antinode = $\lambda/4$ Conclusion:
Therefore, the distance between a node and the adjacent antinode is $\mathbf{\lambda/4}$.
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