Question:
In a single toss of a fair die, the odds against the event that number 4 or 5 turns up is
In a single toss of a fair die, the odds against the event that number 4 or 5 turns up is
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Do not confuse probability with odds.
Odds against = unfavourable : favourable.
Updated On: May 14, 2026
- \(2 : 1\)
- \(1 : 3\)
- \(2 : 3\)
- \(1 : 1\)
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The Correct Option is A
Solution and Explanation
Concept:
Odds against an event are: \[ \text{unfavourable outcomes} : \text{favourable outcomes} \] ip
Step 1: Find favourable outcomes.
The event is that 4 or 5 turns up. So favourable outcomes are: \[ \{4,5\} \] Hence number of favourable outcomes: \[ 2 \] ip
Step 2: Find unfavourable outcomes.
A die has 6 outcomes in total. So unfavourable outcomes: \[ 6-2=4 \] ip
Step 3: Write the odds against.
\[ \text{Odds against} = 4:2 = 2:1 \] ip Hence, the correct answer is:
\[ \boxed{(A)\ 2:1} \]
Odds against an event are: \[ \text{unfavourable outcomes} : \text{favourable outcomes} \] ip
Step 1: Find favourable outcomes.
The event is that 4 or 5 turns up. So favourable outcomes are: \[ \{4,5\} \] Hence number of favourable outcomes: \[ 2 \] ip
Step 2: Find unfavourable outcomes.
A die has 6 outcomes in total. So unfavourable outcomes: \[ 6-2=4 \] ip
Step 3: Write the odds against.
\[ \text{Odds against} = 4:2 = 2:1 \] ip Hence, the correct answer is:
\[ \boxed{(A)\ 2:1} \]
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