The fringes have unequal width and unequal intensity.
The fringes have equal width and equal intensity.
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The Correct Option isD
Solution and Explanation
Concept:
In single slit diffraction:
• central maximum is wider than the secondary maxima,
• intensity decreases away from the centre.
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ip
Step 1: Recall fringe width property.
The central bright fringe is the widest.
The secondary bright fringes are narrower.
So widths are not all equal.
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Step 2: Recall intensity property.
The central maximum has highest intensity.
Secondary maxima have lower and decreasing intensities.
So intensities are not all equal.
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Step 3: Identify the incorrect statement.
The statement saying “equal width and equal intensity” is incorrect.
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Hence, the correct answer is:
\[
\boxed{(D)\ \text{The fringes have equal width and equal intensity}}
\]