Question

In a school the periodical examinations are held every month. In a session during April 'X' to March 'X + 1', Rakesh, a student of class IV, section B, appeared for each of the periodical exams. The maximum total marks in each periodical exam is 50. The aggregate marks obtained by him in each periodical exam are given below.

	Year X									Year X+1
Months	April	May	June	July	Aug.	Sept.	Oct.	Nov.	Dec.	Jan.	Feb.	March
Marks	35	37	38	38	41	43	45	45	46	47	48	49

In which periodical exams did Rakesh obtain the highest percentage increase in marks over the previous periodical exams?

• A. May
• B. October
• C. December
• D. September

Hint:

For each option, divide that month's increase over the previous month by the previous month's marks, then compare.

Answer 1

The Correct Option is A

Step 1: Find the absolute increase over the previous month for each listed choice.
May over April: 37 - 35 = 2.
October over September: 45 - 43 = 2.
December over November: 46 - 45 = 1.
September over August: 43 - 41 = 2.

Step 2: Convert each increase into a percentage of the previous month's marks.
May: (2 / 35) x 100 = 5.71%.
October: (2 / 43) x 100 = 4.65%.
December: (1 / 45) x 100 = 2.22%.
September: (2 / 41) x 100 = 4.88%.

Step 3: Compare the four percentages.
5.71% (May) is greater than 4.88% (September), which is greater than 4.65% (October), which is greater than 2.22% (December). May has the highest percentage increase among the given choices.

Step 4: Rule out the other options.
October, December and September all show a smaller percentage rise than May once the increase is measured against their respective previous-month base, since a numerator of 1 or 2 matters more against a smaller base like April's 35 than against a larger base like September's 41 or November's 45.

Final Answer:
Rakesh had his highest percentage increase in May. \[ \boxed{May} \]