Question

In a school the periodical examinations are held every month. In a session during April 'X' to March 'X + 1', Rakesh, a student of class IV, section B, appeared for each of the periodical exams. The maximum total marks in each periodical exam is 50. The aggregate marks obtained by him in each periodical exam are given below.

	Year X									Year X+1
Months	April	May	June	July	Aug.	Sept.	Oct.	Nov.	Dec.	Jan.	Feb.	March
Marks	35	37	38	38	41	43	45	45	46	47	48	49

The total marks obtained in December X is what per cent more than the total marks obtained in June X?

• A. 12.8%
• B. 20.05%
• C. 24.05%
• D. 21.05%

Hint:

Take December marks minus June marks, divide by June marks, then multiply by 100.

Answer 1

The Correct Option is D

Step 1: Read off the two required values from the table.
Marks obtained in December X = 46.
Marks obtained in June X = 38.

Step 2: Apply the percentage change formula.
Percentage more = [(December marks - June marks) / June marks] x 100
= [(46 - 38) / 38] x 100
= (8 / 38) x 100.

Step 3: Simplify the fraction.
8 / 38 = 4 / 19 = 0.2105 (approximately).
0.2105 x 100 = 21.05%.

Step 4: Rule out the other options.
12.8% is too low for an increase of 8 marks over a base of 38. 20.05% and 24.05% come from small arithmetic slips in the division, not from the correct base of 38.

Final Answer:
December X marks are 21.05% more than June X marks. \[ \boxed{21.05\%} \]