In a region, the potential is represented by
V(x,y,z)=6x-8xy-8y+6yz, where V is in volts and x,y,z are in metres. The electric force experienced by a charge of 2 coulomb situated at point (1,1,1) is:
Show Hint
Electric field is always the negative gradient of potential.
Step 1: Electric field is given by
E=- V
Step 2:
( V)/( x)=6-8y,
( V)/( y)=-8x-8+6z,
( V)/( z)=6y
Step 3: At (1,1,1):
E=(2,10,-6)
Step 4: Force F=qE=2(2,10,-6)=(4,20,-12)
Step 5:
|F|=√(4²+20²+12²)=√(560)=4√(35)