Question:
In a reaction,
$(\text{CH}_3)_2\text{CHMgBr} + \text{CO}_2 \xrightarrow[\text{ether}]{\text{dry}} \text{A} \xrightarrow[\text{dilHCl}]{\text{H.OH}} \text{B}$.
Find the product ' B ' of above reaction.
In a reaction,
$(\text{CH}_3)_2\text{CHMgBr} + \text{CO}_2 \xrightarrow[\text{ether}]{\text{dry}} \text{A} \xrightarrow[\text{dilHCl}]{\text{H.OH}} \text{B}$.
Find the product ' B ' of above reaction.
$(\text{CH}_3)_2\text{CHMgBr} + \text{CO}_2 \xrightarrow[\text{ether}]{\text{dry}} \text{A} \xrightarrow[\text{dilHCl}]{\text{H.OH}} \text{B}$.
Find the product ' B ' of above reaction.
Show Hint
$R\text{MgX} + \text{CO}_2 \to R\text{COOH}$. The acid always has one more carbon than the alkyl group of the Grignard reagent.
Updated On: Apr 26, 2026
- Propanoic acid
- 2-Methyl propanoic acid
- Butanoic acid
- 2,2-Dimethyl ethanoic acid
Show Solution
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The Correct Option is B
Solution and Explanation
Step 1: Concept
Grignard reagent ($R\text{MgX}$) reacts with dry ice ($\text{CO}_2$) followed by hydrolysis to form carboxylic acids with one extra carbon.
Step 2: Reaction Analysis
- Reactant: $(\text{CH}_3)_2\text{CHMgBr}$ (Isopropyl magnesium bromide). - Carbonyl Addition: Isopropyl group attaches to the Carbon of $\text{CO}_2$. - Hydrolysis: The intermediate salt forms $(\text{CH}_3)_2\text{CH}-\text{COOH}$.
Step 3: Conclusion
The structure $(\text{CH}_3)_2\text{CHCOOH}$ is 2-Methylpropanoic acid (also known as Isobutyric acid).
Final Answer: (B)
Grignard reagent ($R\text{MgX}$) reacts with dry ice ($\text{CO}_2$) followed by hydrolysis to form carboxylic acids with one extra carbon.
Step 2: Reaction Analysis
- Reactant: $(\text{CH}_3)_2\text{CHMgBr}$ (Isopropyl magnesium bromide). - Carbonyl Addition: Isopropyl group attaches to the Carbon of $\text{CO}_2$. - Hydrolysis: The intermediate salt forms $(\text{CH}_3)_2\text{CH}-\text{COOH}$.
Step 3: Conclusion
The structure $(\text{CH}_3)_2\text{CHCOOH}$ is 2-Methylpropanoic acid (also known as Isobutyric acid).
Final Answer: (B)
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