Question:

In a reaction $A+B\rightarrow P$ rate is doubled when [B] is doubled, and the rate increases by 8 when both [A] and [B] are doubled. The rate law is:

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Total factor = (Factor A)$^{order A} \times$ (Factor B)$^{order B}$. Here $8 = 2^x \times 2^1$.
Updated On: May 15, 2026
  • $r=k[A][B]$
  • $r=k[A]^{2}[B]$
  • $r=k[A][B]^{2}$
  • $r=k[A][B]^{3}$
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The Correct Option is B

Solution and Explanation


Step 1: Concept
The rate law is $r = k[A]^{x}[B]^{y}$. We need to find orders $x$ and $y$.

Step 2: Meaning
"Rate doubled when [B] is doubled" means $2 = 2^{y}$, so $y = 1$.

Step 3: Analysis
"Rate increases by 8 when both are doubled" means $8 = 2^{x} \cdot 2^{y}$. Substituting $y = 1$: $8 = 2^{x} \cdot 2^{1} \Rightarrow 4 = 2^{x}$. This gives $x = 2$.

Step 4: Conclusion
The rate law is $r = k[A]^{2}[B]^{1}$. This corresponds to option (B). Final Answer: (B)
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