Question

In a population with two alleles B and b with frequency \(0.6\) and \(0.4\) in Hardy-Weinberg equilibrium. How many heterozygous individuals in a sample of \(250\) can be expected?

• A. \(30\)
• B. \(60\)
• C. \(90\)
• D. \(120\)

Hint:

Heterozygote frequency is 2pq, multiplied by the sample size.

Answer 1

The Correct Option is D

Step 1: Understanding the Concept
In Hardy-Weinberg equilibrium, the genotype frequencies are \(p^{2} + 2pq + q^{2} = 1\).

Step 2: Heterozygote frequency
With \(p = 0.6\) and \(q = 0.4\), \(2pq = 2 \times 0.6 \times 0.4 = 0.48\).

Step 3: Number of individuals
Expected heterozygotes \(= 0.48 \times 250 = 120\).

Final Answer:
About 120 individuals are expected to be heterozygous. \[ \boxed{\text{(D) }120} \]