Step 1: Understanding the Concept:
\(f = \frac{1}{2l}\sqrt{\frac Tm}\), so \(f\propto\sqrt T\) and \(T\propto f^2\).
Step 2: Calculation:
The frequency rises by 40 percent, so \(f' = 1.4f\). Then \(T' = (1.4)^2T = 1.96T\).
Step 3: Percentage:
The tension increases by \(1.96 - 1 = 0.96\), that is 96 percent. Choosing 40 percent would ignore the square, and 100 percent would be a doubling.
Final Answer:
Tension must be increased by 96 percent, option (C).
\[ \boxed{96\%} \]