Question:

In a nucleotide sequence ATGC, which of the following nucleotide has the unlinked 5' - OH?

Show Hint

Always read nucleotide sequences from left to right as $5'$ to $3'$. The first letter (A, in ATGC) represents the $5'$ terminal nucleotide with the unlinked $5'$-OH/phosphate group, and the last letter (G) represents the $3'$ terminal end with the unlinked $3'$-OH.
  • deoxyadenylate
  • deoxycytidylate
  • deoxythymidylate
  • deoxyguanylate
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept:
Polynucleotide chains (DNA and RNA) are polar structures.
By scientific convention, nucleotide sequences are written and read in the $5'$ to $3'$ direction unless specified otherwise.

Step 2: Detailed Explanation:

Let us analyze the chemical structure and directionality of the given tetranucleotide sequence $5'-\text{ATGC}-3'$:
- In any standard DNA strand, the $5'$ end of the first nucleotide has a free, unlinked $5'$ hydroxyl (or $5'$ phosphate) group.
- The $3'$ hydroxyl group of this first nucleotide is covalently linked via a phosphodiester bond to the $5'$ phosphate of the next nucleotide, continuing down the chain.
- The last nucleotide at the $3'$ end of the sequence has a free, unlinked $3'$ hydroxyl group.
In the sequence ATGC:
- Deoxyadenylate (A) is the first nucleotide at the $5'$ terminus, meaning it possesses the free, unlinked $5'$ hydroxyl group.
- Deoxythymidylate (T) is the second nucleotide.
- Deoxycytidylate (C) is the third nucleotide.
- Deoxyguanylate (G) is the last nucleotide at the $3'$ terminus, possessing the free, unlinked $3'$ hydroxyl group.
Therefore, deoxyadenylate has the unlinked $5'$ hydroxyl group.

Step 3: Final Answer:

The nucleotide with the unlinked $5'$ hydroxyl group is deoxyadenylate.
Was this answer helpful?
0
0

Top ICAR AIEEA Plant Biotechnology Questions

View More Questions