In a fluorescent lamp choke (a small transformer) 100 V of reverse voltage is produced when the choke current changes uniformly from 0.25 A to 0 in a duration of 0.025 ms. The self-inductance of the choke (in mH) is estimated to be ________.
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Correct Answer: 10
Solution and Explanation
\(L=\frac{100\times0.025\times10^{-3}}{0.25}=\frac{2.5\times10^{-3}}{0.25}=10^{-2}\) H \(=10\) mH.
Answer: 10
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