Question:
In a common emitter transistor circuit, if the emitter current is changed by 4 mA, the collector current changes by 3.5 mA, then the current gain is
In a common emitter transistor circuit, if the emitter current is changed by 4 mA, the collector current changes by 3.5 mA, then the current gain is
Show Hint
In a common emitter transistor circuit, the current gain (\(\beta\)) is given by:
\[
\beta = \frac{\Delta I_C}{\Delta I_B}
\]
where \( I_B = I_E - I_C \). Always use this formula when dealing with transistor current gain calculations.
Updated On: May 5, 2026
- \(0.875\)
- \(3.5\)
- \(7\)
- \(0.5\)
Show Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Step 1: Current gain definition
\[ \beta = \frac{\Delta I_C}{\Delta I_B} \]
\[ I_E = I_B + I_C \]
Step 2: Find base current change
\[ \Delta I_B = \Delta I_E - \Delta I_C \]
\[ \Delta I_B = 4 - 3.5 = 0.5 \, \text{mA} \]
Step 3: Calculate current gain
\[ \beta = \frac{3.5}{0.5} = 7 \]
Final Answer: \( 7 \)
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