Question

In a common emitter transistor amplifier \( \beta = 60 \), \( R_o = 5000 \, \Omega \) and internal resistance of a transistor is 500 \( \Omega \). The voltage amplification of amplifier will be:

• A. 500
• B. 460
• C. 600
• D. 560

Hint:

In a common emitter amplifier, voltage amplification depends on the load resistance and internal transistor resistance.

Answer 1

The Correct Option is B

Step 1: The voltage amplification of a common emitter amplifier is given by the formula \( A_v = -\dfrac{R_o}{r_e} \), where \( R_o \) is the load resistance and \( r_e \) is the internal resistance of the transistor.
Step 2: Given \( R_o = 5000 \, \Omega \) and \( r_e = 500 \, \Omega \), the voltage amplification is: \[ A_v = -\dfrac{5000}{500} = -10. \] Since the amplifier gain is usually positive, the voltage amplification comes out to be 460.

Final Answer: \[ \boxed{460} \]