Question

In a common base mode of a transistor, the collector current is 5.488 mA for an emitter current of 5.60 mA. The value of the base current amplification factor \( \beta \) will be:

• A. 49
• B. 50
• C. 51
• D. 48

Hint:

In a common base mode, the base current amplification factor \( \beta \) is the ratio of the collector current to the base current.

Answer 1

The Correct Option is B

Step 1: Relation between collector current, base current, and amplification factor.
The collector current \( I_C \) is related to the base current \( I_B \) and amplification factor \( \beta \) by the formula: \[ I_C = \beta I_B \] Step 2: Calculation of \( \beta \).
The emitter current \( I_E \) is given by: \[ I_E = I_C + I_B \] Substituting the values: \[ 5.60 = 5.488 + I_B \] This gives \( I_B = 0.112 \) mA. Now, we calculate \( \beta \): \[ \beta = \frac{I_C}{I_B} = \frac{5.488}{0.112} = 50 \]
Final Answer: \[ \boxed{50} \]