Question

In a code language, \(m^{\text{th}}\) letter is coded as \((m-1)^{\text{th}}\) letter if \(m\) is odd and \((m+1)^{\text{th}}\) letter if \(m\) is even. Then the code word for ‘FRAME’ is

• A. GTZLD
• B. GSBLD
• C. GSZLD
• D. GSALD

Hint:

Always check whether the alphabet position is odd or even before shifting the letter.

Answer 1

The Correct Option is C

Concept:
The rule is based on the alphabet position of each letter. If the position number is odd, move one letter backward. If the position number is even, move one letter forward.

Step 1: Write positions of letters in FRAME. \[ F=6,\quad R=18,\quad A=1,\quad M=13,\quad E=5 \]

Step 2: Apply the coding rule. Since \(F=6\) is even: \[ F\rightarrow G \] Since \(R=18\) is even: \[ R\rightarrow S \] Since \(A=1\) is odd: \[ A\rightarrow Z \] Since \(M=13\) is odd: \[ M\rightarrow L \] Since \(E=5\) is odd: \[ E\rightarrow D \]

Step 3: Form the code. \[ \text{FRAME}\rightarrow \text{GSZLD} \]

Step 4: Final answer. \[ \boxed{\text{GSZLD}} \]