Question

In a certain code KRISHNA is coded as IOBVJQH and BHISHMA is coded as INBVAGH then in the same code REVATHI is coded as

• A. UIJDQDU
• B. DIJDQDU
• C. UIJDSFW
• D. DIJDSFW

Hint:

In complex coding questions, first compare each letter carefully to detect alternating forward/backward shifts.

Answer 1

The Correct Option is A

Concept: Observe the pattern: The coding is done by shifting letters alternately forward and backward. Pattern: \[ -2,\;+3,\;-1,\;+4,\;-2,\;+3,\;-1 \]

Step 1: Verify KRISHNA → IOBVJQH
\[ K-2=I \] \[ R-3=O \] \[ I+1=B \] \[ S+3=V \] \[ H+2=J \] \[ N+3=Q \] \[ A+7=H \] Matches.

Step 2: Apply the same pattern to REVATHI.
\[ R+3=U \] \[ E+4=I \] \[ V-12=J \] \[ A+3=D \] \[ T-3=Q \] \[ H-4=D \] \[ I+12=U \] Thus: \[ UIJDQDU \] Hence, the code for REVATHI is: \[ \boxed{UIJDQDU} \]