Question:
In a CE transistor amplifier, the signal voltage across the collector resistance is 2.5 V. The input signal voltage is 0.02 V. If the base and collector resistances are 1.5 k\(\Omega\) and 2.5 k\(\Omega\), find the current amplification factor.
In a CE transistor amplifier, the signal voltage across the collector resistance is 2.5 V. The input signal voltage is 0.02 V. If the base and collector resistances are 1.5 k\(\Omega\) and 2.5 k\(\Omega\), find the current amplification factor.
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In CE amplifier, \(\beta = \frac{V_C R_B}{V_B R_C}\). Always consider collector and base resistor ratios along with voltage signals.
Updated On: Jul 18, 2026
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The Correct Option is C
Solution and Explanation
Step 1: Recall CE amplifier current amplification formula.
\[ \beta = \frac{I_C}{I_B} \approx \frac{V_C / R_C}{V_B / R_B} = \frac{V_C R_B}{V_B R_C} \]
Step 2: Substitute given values.
\[ V_C = 2.5 \, \text{V}, \quad V_B = 0.02 \, \text{V}, \quad R_C = 2.5 \, \text{k}\Omega, \quad R_B = 1.5 \, \text{k}\Omega \]
Step 3: Apply formula.
\[ \beta = \frac{2.5 \cdot 1.5}{0.02 \cdot 2.5} = \frac{3.75}{0.05} = 75 \]
Step 4: Check reasoning.
CE current amplification factor consistent with voltage ratio and resistor ratio.
Step 5: Conclude.
The current amplification factor of the transistor is:
\[ \boxed{75} \]
\[ \beta = \frac{I_C}{I_B} \approx \frac{V_C / R_C}{V_B / R_B} = \frac{V_C R_B}{V_B R_C} \]
Step 2: Substitute given values.
\[ V_C = 2.5 \, \text{V}, \quad V_B = 0.02 \, \text{V}, \quad R_C = 2.5 \, \text{k}\Omega, \quad R_B = 1.5 \, \text{k}\Omega \]
Step 3: Apply formula.
\[ \beta = \frac{2.5 \cdot 1.5}{0.02 \cdot 2.5} = \frac{3.75}{0.05} = 75 \]
Step 4: Check reasoning.
CE current amplification factor consistent with voltage ratio and resistor ratio.
Step 5: Conclude.
The current amplification factor of the transistor is:
\[ \boxed{75} \]
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