Concept:
Continuous growth:
\[
P(t) = P_0 e^{rt}
\]
Step 1: Given condition.
Initial amount = 100, final amount = 200, time = 10 years
\[
200 = 100 e^{rt}
\]
Step 2: Simplify.
\[
2 = e^{10r}
\]
Step 3: Take log.
\[
\ln 2 = 10r
\]
\[
r = \frac{0.6931}{10} = 0.06931
\]
Step 4: Convert to percentage.
\[
x = 0.06931 \times 100 = 6.93%
\]
Step 5: Conclusion.
\[
x = 6.93%
\]