Question

In a △ ABC, if (cos A)/(a)=(cos B)/(b)=(cos C)/(c), and the side a=2, then area of the triangle is:

• A. \(1\)
• B. \(2\)
• C. \(\dfrac{\sqrt{3}}{2}\)
• D. √(3)

Hint:

Symmetry in cosine relations often indicates an equilateral triangle.

Answer 1

The Correct Option is C

Given condition implies the triangle is equilateral. Thus, a=b=c=2 Area: =frac√(3)4a²=frac√(3)2