Question:

In a 120 litre solution of acid and water, acid is \(75%\). A person takes out 20 litres of this solution and adds \(16.2\) litres of acid and \(3.8\) litres of water in the remaining solution. What is the percentage of water in the final solution?

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When quantities are removed from a mixture, remove them in the same proportion of the components, then add new amounts. Track each component separately for accuracy.
Updated On: Aug 14, 2025
  • \(22\)
  • \(24\)
  • \(25\)
  • \(28\)
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The Correct Option is B

Solution and Explanation

Step 1: Initial quantities.
In \(120\) litres, acid = \(75%\) of \(120 = 90\) L,
water = \(25%\) of \(120 = 30\) L.
Step 2: Remove \(20\) litres of solution.
Acid removed = \(75%\) of \(20 = 15\) L,
water removed = \(5\) L.
Remaining acid = \(90 - 15 = 75\) L,
Remaining water = \(30 - 5 = 25\) L.
Remaining quantity = \(100\) L.
Step 3: Add \(16.2\) L acid and \(3.8\) L water.
New acid = \(75 + 16.2 = 91.2\) L,
New water = \(25 + 3.8 = 28.8\) L.
Total = \(91.2 + 28.8 = 120\) L.
Step 4: Find percentage of water.
\[ \text{Water %} = \frac{28.8}{120} \times 100 = 24%. \] \[ \boxed{24%} \]
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