We are given \(\frac{z}{i} = 11 - 13i\), and we need to find \(z + \bar{z}\).
First, multiply both sides of the equation by \(i\) to find \(z\):
\(z = i(11 - 13i)\)
Now, distribute \(i\):
\(z = 11i - 13i^2\)
Since \(i^2 = -1\), we have:
\(z = 11i + 13\)
Now, we find \(\bar{z}\), the conjugate of \(z\):
\(\bar{z} = 13 - 11i\)
Now, calculate \(z + \bar{z}\):
\(z + \bar{z} = (13 + 11i) + (13 - 11i) = 13 + 13 = 26\)
The answer is 26.
If $ | \vec{a} | = 3 $, $ | \vec{b} | = 2 $, then find $ (3\vec{a} - 2\vec{b}) \cdot (3\vec{a} + 2\vec{b}) $.
If $ | \vec{a} | = 3 $, $ | \vec{b} | = 2 $, then find $ (3\vec{a} - 2\vec{b}) \cdot (3\vec{a} + 2\vec{b}) $.