Concept:
The intercepts of a line are the points where the line crosses the axes. To find these from a linear equation $Ax + By = C$:
• The x-intercept is found by setting $y = 0$.
• The y-intercept is found by setting $x = 0$.
• Alternatively, convert the equation to the intercept form $\frac{x}{X} + \frac{y}{Y} = 1$, where $X$ is the x-intercept and $Y$ is the y-intercept.
Step 1: Calculate the x-intercept.
Set $y = 0$ in the equation $4x - ay = 8$:
\[
4x - a(0) = 8 \quad \Rightarrow \quad 4x = 8 \quad \Rightarrow \quad x = 2
\]
So, the x-intercept is $2$.
Step 2: Calculate the y-intercept.
Set $x = 0$ in the equation $4x - ay = 8$:
\[
4(0) - ay = 8 \quad \Rightarrow \quad -ay = 8 \quad \Rightarrow \quad y = -\frac{8}{a}
\]
So, the y-intercept is $-\frac{8}{a}$.
Step 3: Use the given condition to solve for $a$.
The problem states that the y-intercept is thrice (3 times) the x-intercept:
\[
-\frac{8}{a} = 3 \times 2
\]
\[
-\frac{8}{a} = 6
\]
Multiplying both sides by $a$ and dividing by $6$:
\[
a = -\frac{8}{6} = -\frac{4}{3}
\]