Question:

If \(y = \frac{3}{\sqrt{2}}\left(\sin \frac{\pi}{4}t + \cos \frac{\pi}{4}t\right)\) cm represents simple harmonic motion, the time period of the motion is:

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Convert sum of sine and cosine into single sine or cosine using amplitude-phase formula to identify angular frequency and period.
Updated On: Jun 19, 2026
  • 8 s
  • 10 s
  • 6 s
  • 12 s
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The Correct Option is A

Solution and Explanation

Step 1: Express in standard SHM form.
\[ y = \frac{3}{\sqrt{2}} \left( \sin \frac{\pi}{4}t + \cos \frac{\pi}{4}t \right) = \frac{3}{\sqrt{2}} \sqrt{2} \sin\left(\frac{\pi}{4}t + \frac{\pi}{4}\right) = 3 \sin\left(\frac{\pi}{4}t + \frac{\pi}{4}\right) \]

Step 2: Identify angular frequency.

For standard SHM \(y = A \sin(\omega t + \phi)\), \(\omega = \frac{\pi}{4}\ \text{rad/s}\).

Step 3: Find period.

\[ T = \frac{2\pi}{\omega} = \frac{2\pi}{\pi/4} = 8~\text{s} \]

Step 4: Conclusion.

Hence, the time period of motion is 8 s.
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